BPSC TRE-2: Apply for 1.22 Lakh Teacher Recruitment Registration Today Last Date, 25th November- CMB College

BPSC TRE-2: Apply for 1.22 Lakh Teacher Recruitment Registration Today Last Date, 25th November

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BPSC TRE-2: Today is the last date for registration in Bihar Public Service Commission Phase II Teacher Recruitment Examination (BPSC TRE-2). Candidates willing to apply for Bihar 1.22 Lakh Teacher Recruitment 2023 can complete their registration by 14th November evening. Registered candidates will have time till 25 November 2023 to fill the online application form. That means only the candidates who have registered till today evening can fill the form on Commission website www.bpsc.bih.nic.in till the last date of application. The Commission has made it clear that the last date of application will not be extended. Also, as last time, candidates appearing for B.Ed and CTET exams will not be given the opportunity to apply in TRE-2.

BPSC Chairman Atul Prasad announced the new Teacher Recruitment 2023 on 4 November 2023. The commission chairman said that registration for New Bihar Teacher Recruitment can be done from November 5 to November 14 and application can be made from November 10 to November 25, 2023. Let us tell you that in this BPSC recruitment advertisement was released for 70 thousand posts in which more than 50 thousand 600 posts have been added. That means now the suitable candidates will be selected for a total of 1.22 lakh posts.

Important changes in the examination for recruitment of new teachers were also given. The commission chairman said that in view of the problems faced by the candidates in the process of TI-1, some changes have been made in some teacher recruitment examinations. The major change in the Bihar Teacher Recruitment Exam is that now the exam will be conducted in one day instead of two days. Also, instead of two papers, there will be only one paper. Also now there will be no minus marking in teacher recruitment exam.

New Rule for Tie Breaker:
Part 2 and Part 3 of the paper combined will have a total of 120 marks for the merit list. If there is a tie breaker result then the eligible candidate will be selected based on the marks in Part-III. If there is a tie breaker in Part 3 also, the language which scores more marks, which is of a qualifying nature, will be considered qualified. Name and date of birth will be given preference if there are equal marks in language subject.

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